The size is 7.

avg_row_len includes the row header.

dba_tab_columns.data_length has the "correct" result 7.

The length function applies to varchar2 fields, so the date is converted to a 
character using your default date format, and the length of the string is returned. 
length ('06-OCT-03') = 9


> -----Original Message-----
> elain he
> 
> I'm trying to figure out the size (in bytes) of a DATE 
> column. Executing the 
> three queries below returned me three different values. Is 
> there any way of 
> finding the size of a date column in the database?
> 
> select * from testing;
> DOB
> ---------
> 06-OCT-03
> 
> 
> desc testing
> Name                                                          
>            
> Null?    Type
> --------------------------------------------------------------
> ---------- 
> -------- -------------
> DOB                                                           
>                
>       DATE
> 
> 
> select avg_row_len from user_tables where table_name='TESTING';
> AVG_ROW_LEN
> -----------
>          11
> 
> 
> select data_length from dba_Tab_columns where table_name='TESTING';
> DATA_LENGTH
> -----------
>           7
> 
> 
> select length (timestamp) from abc;
> LENGTH(TIMESTAMP)
> -----------------
>                 9
-- 
Please see the official ORACLE-L FAQ: http://www.orafaq.net
-- 
Author: Jacques Kilchoer
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