Try:
SELECT segment_type,
segment_name,BLOCKS*8192/1024 "Kb"
FROM DBA_SEGMENTS
WHERE OWNER=UPPER('<owner>') AND SEGMENT_NAME = UPPER('<table_name>');
FROM DBA_SEGMENTS
WHERE OWNER=UPPER('<owner>') AND SEGMENT_NAME = UPPER('<table_name>');
Tony
-----Original Message-----
From: Pillai, Rajesh [mailto:[EMAIL PROTECTED]
Sent: Wednesday, October 15, 2003 3:24 PM
To: Multiple recipients of list ORACLE-L
Subject: Table SizeHi All,Could somebody help me in finding the actual size of an oracle table in GB.TIA,Rajesh