Will this work?
------------------------------------------------------
#!/usr/bin/ksh
THINGY=0
cat swt | sed 's/:/ /' | while read A B JUNK; do
if [ $THINGY -eq 1 ]; then
B="that"
THINGY=0
else
THINGY=1
fi
echo "$A:$B $JUNK"
done
------------------------------------------------------
You can set up a similar loop in awk too.
The sed 's/:/ /' changes the colon to a space so that the read A B JUNK will
work.
> -----Original Message-----
>
> Hi List
> I need some help on this;
> How do i replace the 2nd,4th,6th occurances of a column
> (vertical) in a
> file.
> I know sed does it within a row
>
> $ cat swt
> 01:this is a file1 this
> 02:this is a file1 this
> 03:this is line3
> 04:this is line4
>
> $ sed 's/this/that/2' swt
> 01:this is a file1 that
> 02:this is a file1 that
> 03:this is line3
> 04:this is line4
> $ sed 's/this/that/1' swt
> 01:that is a file1 this
> 02:that is a file1 this
> 03:that is line3
> 04:that is line4
>
> But i want
> 01:this is a file1 this
> 02:that is a file1 this
> 03:this is line3
> 04:that is line4
>
> I tried awk but awk seems to be going one line at a time.
>
> Thanks in Advance.
>
> GovindanK
>
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