Hi: In pl/sql, I want to add chr(10) into a string in every 70th position. The string can be up to 2000 characters long. The follwoing code works. But is there an even FASTER way to do this?
Thanks. Guang --- declare pos number := 1; len number; buf varchar2(2000); x varchar2(2100); begin buf := '012345678901234567890123456789012345678901234567890123456789012345678901234 5678901234567890123456789012345678901234567890123456789012345678901234567890 12345678901234567890123456789012345678901234567890123456789A'; len := length(buf); while pos<=len loop x := x || substr(buf, pos, 70) || chr(10); pos := pos+70; end loop; end; -- Please see the official ORACLE-L FAQ: http://www.orafaq.net -- Author: Guang Mei INET: [EMAIL PROTECTED] Fat City Network Services -- 858-538-5051 http://www.fatcity.com San Diego, California -- Mailing list and web hosting services --------------------------------------------------------------------- To REMOVE yourself from this mailing list, send an E-Mail message to: [EMAIL PROTECTED] (note EXACT spelling of 'ListGuru') and in the message BODY, include a line containing: UNSUB ORACLE-L (or the name of mailing list you want to be removed from). You may also send the HELP command for other information (like subscribing).