Here is an example for you.
You might want to spend some more time studying the instr() function in the SQL
manual to understand how this works. :)
define t = 'mystr1~mystr2~mystr3'
var t varchar2(30)
begin
select '&&t' into :t from dual;
end;
/
select
substr(:t,1,instr(:t,'~')-1) t1
, substr(:t,instr(:t,'~')+1, instr(:t,'~')-1) t2
, substr(:t,instr(:t,'~',instr(:t,'~')+1)+1, instr(:t,'~')-1) t2
from dual
/
or the somewhat simpler:
select
substr(:t,1,instr(:t,'~')-1) t1
, substr(:t,instr(:t,'~')+1, instr(:t,'~')-1) t2
, substr(:t,instr(:t,'~',1,2)+1, instr(:t,'~')-1) t2
from dual
/
HTH
Jared
| Stefick Ronald S Contr ESC/HRIDA <[EMAIL PROTECTED]>
Sent by: [EMAIL PROTECTED] 01/26/2004 03:29 PM
|
To: Multiple recipients of list ORACLE-L <[EMAIL PROTECTED]> cc: Subject: String manipulation |
I'm trying to separate a string into 3 values:
The string is:
mystr1~mystr2~mystr3
Here is the code so far:
1 select substr(subject,1,instr(subject,'~')-1) first,
2 substr(subject,instr(subject,'~')+1, instr(subject,'~',1,2)-1) second,
3 substr(subject,instr(subject,'~',1,2)+1,length(subject))
4 from test_table
5 where test_column=1700455
The result I get is:
mystr1
mystr2~mystr3
mystr3
The result I want is:
mystr1
mystr2
Mystr3
TIA,
Scott Stefick
MILPDS OCP Oracle DBA
[EMAIL PROTECTED]
210-565-2540
