>> I just started working with RegExp's so, I'm totally hacking this.
I love this little program: http://www.regexbuddy.info <http://www.regexbuddy.info/> It'll make your life a whole lot easier - it will even explain every function of regex as you type it, or decompile a regex into a human readable form. I find it invaluable (as I do a lot of validation etc) It's also got a testing bit where it'll highlight matches from a page of text, which is useful too. Antony Jones Developer Gamesys Limited e: [EMAIL PROTECTED] t: 0207 478 8103 a: 1st Floor, 54-62 Regent Street, LONDON, W1B 5RE Save trees and protect the environment - think before you print this email! ________________________________ From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of John Grden Sent: 07 June 2007 02:56 To: Open Source Flash Mailing List Subject: Re: [osflash] RegExp question Sounds good to me! What's \s? yeah, basicall, that was it - forcing it to have a valid space between the 2 I just started working with RegExp's so, I'm totally hacking this. On 6/6/07, Darren Cook <[EMAIL PROTECTED]> wrote: > it's supposed to catch a "yy hh:mm" string, but when I pass 4 digit > year, it > still says true. It also optionally allows for 12hr clock values (hence > the alternation with the am/pm) > > var reg:RegExp = /^\b(\d{2})\b[ > ]\b(?:(?:0?[1-9]|1[012])(?:[.:][0-5]\d){1,2}(?:\D?[ap][m]))|(?:[01]*\d|2 [0-3])\b[.:]\b[0-5]\d\b$/i; > > trace(reg.test("1969 21:00")); I've always used "\s*" the way you are using "\b". But I think you always want one whitespace character between year and time? Is that what the \b[ ] thing is doing? How about replacing "^\b(\d{2})\b[ ]\b" with "^\s*(\d{2})\s+". Darren -- Darren Cook http://dcook.org/mlsn/ (English-Japanese-German-Chinese free dictionary) http://dcook.org/work/ (About me and my work) http://dcook.org/work/charts/ (My flash charting demos) _______________________________________________ osflash mailing list [email protected] http://osflash.org/mailman/listinfo/osflash_osflash.org -- [ JPG ]
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