Hi John,
Also, as a side note, how do I convert osg::Node* to osg::Node& ?
This is a basic C/C++ programming question. Node* is a pointer-to-Node,
and Node& is a reference-to-Node. The quick answer is:
osg::Node* node_pointer = new osg::Node;
osg::Node& node_reference = *node_pointer;
osg::Node* other_node_pointer = &node_reference;
On line 2, * is "dereference" which dereferences a pointer.
On line 3, & is "address-of" which returns the address of a variable
(which you can store in a pointer). The new on line 1 allocates memory
for an object of the size of the Node class, calls its constructors, and
returns the address of that new instance.
But be careful not to dereference a null or uninitialized pointer:
osg::Node* uninitialized_node;
osg::BoundingSphere bs1 = uninitialized_node->getBound(); // crash
osg::Node& uninitialized_node_reference = *uninitialized_node;
osg::BoundingSphere bs2 = node.getBound(); // crash
osg::Node* null_node = NULL; // or = 0
osg::BoundingSphere bs3 = null_node->getBound(); // crash
osg::Node& null_node_reference = *null_node; // crash
osg::BoundingSphere bs4 = null_node_reference.getBound(); // crash
Note above the -> and . operators... var->method() is equivalent to
(*var).method(). So . is "call on variable or reference" whereas -> is
"dereference and call" or "call method on pointer".
For more details please see a C/C++ textbook... I've already said more
than I should have... ;-)
J-S
--
______________________________________________________
Jean-Sebastien Guay jean-sebastien.g...@cm-labs.com
http://www.cm-labs.com/
http://whitestar02.webhop.org/
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