Thanks for the explanations.

d_a_heitbrink wrote:
> 
> As per the inout, this states the parameter into the function is both an 
> input and an output. I set the version for my shader to something like 4.5 in 
> compatibility mode. The function was called last in my shader.
> 

I was just asking how do you get the value of color parameter passed to the 
function not the meaning of "inout" (I already read that from documentation ;))

Regards,
Gianni

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