HI Wendell,
Thank you very much. Works like a charm.
Regards,
Frank
------------------------------------------------------------------------
Am 22.02.2023 um 14:22 schrieb Wendell Piez:
Frank,
There is an interesting feature of Schematron's design useful in a
case like yours, namely that within a pattern, only one rule may apply
to any element, and the first rule wins.
This means we can pre-empt the application of rules by writing other
rules.
For example:
<sch:pattern id="Check_LI">
<sch:rule context="*[exists(@conref)]//li | li[exists(@conref)]"/>
<sch:rule context="li">
<sch:assert test="exists(*)">li must have children</sch:assert>
</sch:rule>
</sch:pattern>
The second rule says "an li must have children". The first rule
intervenes for li elements that have @conref or an ancestor with
@conref - it does no checking so it is silent.
Try it and see how it goes --
Cheers, Wendell
------------------------------------------------------------------------
On Wed, Feb 22, 2023 at 7:35 AM Frank Dissinger
<[email protected]> wrote:
Hi all,
I need a Schemtron rule which indicates an error when <li>
elements do not have any child elements. No error schould be
indicated for <li> elements with an "conkeyref" attribute and also
for <li> elements which are children of any element with a
"conkeyref" attribute.
I have defined two separate rules...
<sch:pattern id="Check_LI2">
<sch:rule context="*li[not(@conkeyref)]*">
<sch:assert test="*">List does not contain any child
elements</sch:assert>
</sch:rule>
</sch:pattern>
<sch:pattern id="Check_LI3">
<sch:rule context="*li[not(parent::*[@conkeyref])]*">
<sch:assert test="*">List does not contain any child
elements</sch:assert>
</sch:rule>
</sch:pattern>
... but I think I need to combine them into a single rule with an
OR or AND operator.
<sch:pattern id="Check_LI3">
<sch:rule context="*li[not(@conkeyref)]* *OR
**li[not(parent::*[@conkeyref])] *">
<sch:assert test="*">List does not contain any child
elements</sch:assert>
</sch:rule>
</sch:pattern>
However, this syntax is invalid. Can somebody help me?
Regards,
Frank
--
*Frank Dissinger*
Documentation Manager
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