https://bugzilla.redhat.com/show_bug.cgi?id=1529023



--- Comment #6 from Björn "besser82" Esser <besse...@fedoraproject.org> ---
(In reply to David Carlos from comment #5)
> (In reply to Björn "besser82" Esser from comment #4)
> > > - Your License field defines BSD as the package license, but upstream uses
> > > MIT.
> > > I had notices that the upstream setup.py file defines the license as BSD,
> > > but the LICENSE file is MIT.
> > > I don't have enough knowledge about licensing but this appear
> > > a bit inconsistent to me.
> > 
> > > [!]: License field in the package spec file matches the actual license.
> > >      Note: Checking patched sources after %prep for licenses. Licenses
> > >      found: "MIT/X11 (BSD like)", "BSD (unspecified)", "Unknown or
> > >      generated", "*No copyright* BSD (unspecified)". 48 files have unknown
> > >      license. Detailed output of licensecheck in
> > >      /home2/david/rpmbuild/REVISIONS/1529023-python-
> > >      validators/licensecheck.txt
> > 
> > Well, there is very little difference in these licenses.  On Pypi the
> > package is distributed as BSD licensed…  That's why I didn't complain about
> > it.
> > 
> > The only real difference between those two licenses is:  BSD *requires* you
> > to redistribute the license file, MIT does not (It just recommends 'shall
> > be' to do it).
> > 
> > For a Fedora package this difference is not relevant, since we require to
> > redistribute the license file along with the SRPM and the binary RPMs by our
> > guidelines.
> > 
> 
> We are packaging a license file containing a MIT license description, but
> the license spec field defines the license as BSD. If this is relevant or
> not, I really don't know, but is inconsistent. In my point of view this is
> not a packaging problem, but was a decision made by the upstream (in my
> opinion, a inconsistent decision) that is making the license spec field and
> the license file be different.

Then that *should* be discussed with upstream and changed in a new release of
the package…


> > > [!]: Package meets the Packaging Guidelines::Python
> > 
> > I don't get the reason, why the package doesn't comply to the additional
> > Python guidelines…
> 
> William should use the python macros defined on the guidelines, as I pointed
> on the review.

Mhh…  'should' != 'must' and thus doesn't violate the guidelines.  Or is my
logic wrong here?

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