>Is there a palm c function that returns the square root of a float?
>If not, does anyone have an algorithm that would work. I want to
Try this one.
Regards,
Steve Mann
# # #
/*****************************************************
__sqrt
Calculate the square root of a double number.
*****************************************************/
double __sqrt ( double number ) {
double result = ZERO, square = ZERO, diff = ZERO;
UInt cnt = 0;
// eliminate negatives and zeros
if ( number <= ZERO ) result = ZERO;
else {
result = number; // initial approximation
// loop until required precision is attained or loop counts out
do {
result = ( result + number / result ) / TWO;
cnt++;
square = result * result; // only for
calculating termination
diff = square - number;
} while (( diff > ZERO ) && ( cnt < 30 )) ;
}
return result;
}
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