> >Does this single quote convention mean that each character in the 'string'
> >represents a byte in a 4-byte value?
>
> It means each char is an eight-bit ASCII char. Each gets stored in
> one byte of the ULong.
had to put my nose in here :P
C is a very non-strict type language.. you can assign a char to an
int very esialy without the compiler complaining..
ie:
int c = 'A';
converts the 'A' into its ASCII equivalent.. being 65 :) c is now
got the value of 65.
when you deal with more than one char, it treats it as a larger number,
where each character represents 8bits in the number.
ie:
int c = 'ABCD';
will assign the number of 0x41424344 (someone please correct me if
i am wrong) :> the hex values 0x41 = 'A', 0x42 = 'B'. etc.
the same thing could be done as follows:
unsigned char *p;
int c;
p = &c;
*p++ = 'A';
*p++ = 'B';
*p++ = 'C';
*p++ = 'D';
but you can see how tedious that is.. the C compiler is much nicer
to us :) there are loads of features like this in C - its no surprise
people done like it.. but personally.. one of the BEST languages i
have ever used, if used correctly :P
hope this explains your questions!
az.
--
Aaron Ardiri
Java Certified Programmer http://www.hig.se/~ardiri/
University-College i G�vle mailto:[EMAIL PROTECTED]
SE 801 76 G�vle SWEDEN
Tel: +46 26 64 87 38 Fax: +46 26 64 87 88
Mob: +46 70 656 1143 A/H: +46 8 668 78 72
if you enjoy it, then it aint work :) - rule #106 of life
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