> From: Jeremy Nuss
>
> The following code aught to work properly then.
>
> char ** memptr;
> memptr = (char**)MemPtrNew(sizeof(char*) * items);
> memptr[n] = (char *)MemPtrNew(StrLen("Some String") + 1);
> for(UInt i = 0; i < (sizeof(memptr)/sizeof(char *)); i++)
> {
> MemPtrFree(memptr[i]);
> }
> MemPtrFree(memptr);
>
Well, not really. What is n in memptr[n]? What about each memptr[x], where
1 <= x <= items? For a completely useless example that will "work" (though
I didn't bother to test it):
Char ** memptr;
UInt16 i, items = 10; // for example
// allocate an array of pointers
memptr = (Char**)MemPtrNew(sizeof(Char*) * items);
for(i = 0; i < items; i++)
memptr[i] = (Char *)MemPtrNew(StrLen("Some String") + 1);
// free the array of pointers
for(i = 0; i < items; i++)
MemPtrFree(memptr[i]);
MemPtrFree(memptr);
I moved the declaration of i to the top because I'm using C, not C++. That
change shouldn't have any impact on the code under C++.
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