Greetings, Is the MemMove function actually relocating the bytes, or just making a copy? The documentation does not specify this, and to me a *move* means you are dealing with and moving only one set of data.
If this is a true move, what happens to the memory locations that originally held the data? Are they set to a specific value or left alone? If they are left alone, then this function is really a MemCopy and the chosen name is just a poor one? Basically what I'm asking is can I treat this like the standard C memcpy() function? Thanks, Matthew -- For information on using the Palm Developer Forums, or to unsubscribe, please see http://www.palmos.com/dev/support/forums/
