On Sat, Feb 3, 2018 at 10:05 PM, Emil Fihlman <[email protected]> wrote: > At the same time the documentation says: > > --jobs N > -j N > --max-procs N > -P N Number of jobslots on each machine. Run up to N jobs in > parallel. > 0 means as many as possible. Default is 100% which will run > one > job per CPU core on each machine.
This is when you do not use --nonall. When using --nonall the documentation for --nonall takes precedence. > So it should by default run a single job on each machine. By default it should determine the number of cores on your local machine and run that many jobs in parallel. So on an 8 core machine it will log into 8 machines in parallel. I still think what you are looking for is '-j0'. /Ole
