Hey Berk,

Say I have a pipeline with a box and point source, from the Python shell (CVS Feb 18, 2009):

Python 2.5.2 |EPD 2.5.2001| (r252:60911, Aug 4 2008, 13:45:20)
[GCC 4.0.1 (Apple Computer, Inc. build 5370)] on darwin
>>> from paraview.simple import *
>>> pm = servermanager.ProxyManager()
>>> pm.GetProxiesInGroup("sources")
{('Box1', '363'): <paraview.servermanager.Box object at 0x224c5670>, ('PointSource1', '114'): <paraview.servermanager.PointSource object at 0x224c5530>}
>>>

I can program around it, but I was just curious what the the second member of the tuple is for.

-Eric


On Feb 23, 2009, at 9:03 PM, Berk Geveci wrote:

GetProxiesInGroup() should return a dictionary where the keys are the
proxy names and the values are the proxies themselves. Is that not the
case?

-berk

On Thu, Feb 19, 2009 at 3:30 PM, Eric E. Monson <[email protected]> wrote:
Hey,

I was just trying out some python state loading (outside of ParaView) for
saving animations, and my old scripts are not working.

pm = servermanager.ProxyManager()
pm.GetProxiesInGroup("sources")

now seems to return a dictionary where the keys are a tuple of two strings (a name and a number) instead of just a name string. Has something changed
in CVS recently, or am I doing something screwy?

Thanks,
-Eric

------------------------------------------------------
Eric E Monson
Duke Visualization Technology Group



_______________________________________________
Powered by www.kitware.com

Visit other Kitware open-source projects at
http://www.kitware.com/opensource/opensource.html

Please keep messages on-topic and check the ParaView Wiki at:
http://paraview.org/Wiki/ParaView

Follow this link to subscribe/unsubscribe:
http://www.paraview.org/mailman/listinfo/paraview


_______________________________________________
Powered by www.kitware.com

Visit other Kitware open-source projects at 
http://www.kitware.com/opensource/opensource.html

Please keep messages on-topic and check the ParaView Wiki at: 
http://paraview.org/Wiki/ParaView

Follow this link to subscribe/unsubscribe:
http://www.paraview.org/mailman/listinfo/paraview

Reply via email to