thanks for the hint but m'i unable to find a way to map the filter id to the data ID (inside the python view script )
def Render(View,figure): from paraview.simple import * names = { x[1]:x[0] for x in GetSources().keys()} print(names) for i in xrange(view.GetNumberOfVisibleDataObjects()): print(view.GetVisibleRepresentation(i).GetUniqueIdentifier()) 2016-10-13 10:14 GMT+02:00 <postgu...@web.de>: > Hi Felipe > > Would GetSources(), maybe along with FindSource and SetActiveSource help > you? > ALL=GetSources() gives you a dictionary of all sources in your session. > > Cheers > Venke > > > > > Felipe Bordeu <felipebor...@gmail.com> hat am 12. Oktober 2016 um 15:15 > > geschrieben: > > > > > > I use python view to plot some data allons my 3D visualisation. Can I get > > the name of the source inside the 'python view script' so I can know to > > which source belongs each line on my plot?. > > (I know I can set the name of a source using RenameSource('Good Result > ') > > ) > > > > > > Felipe > > _______________________________________________ > > Powered by www.kitware.com > > > > Visit other Kitware open-source projects at > > http://www.kitware.com/opensource/opensource.html > > > > Please keep messages on-topic and check the ParaView Wiki at: > > http://paraview.org/Wiki/ParaView > > > > Search the list archives at: http://markmail.org/search/?q=ParaView > > > > Follow this link to subscribe/unsubscribe: > > http://public.kitware.com/mailman/listinfo/paraview >
_______________________________________________ Powered by www.kitware.com Visit other Kitware open-source projects at http://www.kitware.com/opensource/opensource.html Please keep messages on-topic and check the ParaView Wiki at: http://paraview.org/Wiki/ParaView Search the list archives at: http://markmail.org/search/?q=ParaView Follow this link to subscribe/unsubscribe: http://public.kitware.com/mailman/listinfo/paraview