Thanks Tim;

I could precisely extract the bubble using the threshold filter as you said 
(attached picture).

Coming to the 2nd step: I applied the integrate variables filter on the 
threshold data but I get the general data set values within individual cells 
like the computed velocity, pressure, etc....

How do I integrate the the region in space to find the enclosed volume?

Sorry, if it's a basic question.

Saideep

From: Gallagher, Timothy P [mailto:tim.gallag...@gatech.edu]
Sent: 04 March 2017 17:09
To: Saideep Pavuluri <saideep.pavul...@pet.hw.ac.uk>; paraview@paraview.org
Subject: Re: Finding volume enclosed by a contour.


Your best bet would be to use the Threshold filter to extract the region where 
the scalar is greater (or less than) 0.5 and then use the IntegrateVariables 
filter on the Threshold.



It's not entirely clear your exact pipeline, but it sounds like you are using 
the IntegrateVariables filter on the Contour, which would give you the surface 
area of the region instead.



Tim

________________________________
From: ParaView 
<paraview-boun...@paraview.org<mailto:paraview-boun...@paraview.org>> on behalf 
of Saideep Pavuluri 
<saideep.pavul...@pet.hw.ac.uk<mailto:saideep.pavul...@pet.hw.ac.uk>>
Sent: Saturday, March 4, 2017 11:36 AM
To: paraview@paraview.org<mailto:paraview@paraview.org>
Subject: [Paraview] Finding volume enclosed by a contour.


Hi guys;



I am using a numerical method (Volume of fluid, just for information) to look 
at the breaking of a bubble in a micro-channel. Attached picture.



As mostly, the bubbles are of uniform size, I would like to know the volume of 
any one bubble formed.



The bubble is represented by a scalar data set represented by 1 and bounded by 
the same data set with values 0.



I think to clip the region enclosing one bubble and draw a contour where the 
scalar value is 0.5. Now, I tried the integrate variables filter but I did not 
find a data representing the volume.  Any idea how can I get the volume 
enclosed by this contour?



Any help appreciated.



Thanks;

SaiD
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