> On Mon, Nov 09, 2015 at 03:20:39PM +0000, Finucane, Stephen wrote: > > > That wouldn't work either. On the last iteration (count - 1)/count > would > > > be printed and count/count would never be printed. > > > > Right you are. What on earth was that code doing there at all? :) > > Actually, because i goes from 0 to count - 1, another option is to print > (i + 1)/count, and the i == count - 1 condition could then ben used.
Which option would you prefer? Stephen _______________________________________________ Patchwork mailing list Patchwork@lists.ozlabs.org https://lists.ozlabs.org/listinfo/patchwork
