Thanks, but the one they are calling "Accurate" is the same one I'm using as
best as I can tell. I don't need to split the the octets.

Thanks,
Adrian

On Wed, Dec 1, 2010 at 5:14 PM, teacher1st <[email protected]> wrote:

>  Some suggestions here:
>
> http://answers.oreilly.com/topic/318-how-to-match-ipv4-addresses-with-regular-expressions/
>
>
>
> On 12/1/2010 4:08 PM, Adrian Crenshaw wrote:
>
> Hi All,
>     I've Googled around and not had much luck finding something better. I'm
> trying to parse a file in Python and extract all IPs. Currently I'm using:
>
>
> IPsInFile =
> re.findall('(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)',TextBlob)
>
> But this gives me some bad results such as:
>
> .106
> .123.102
> .128
> .143
> .144
> .186.64
> .190
> .2
> .200.65
> .208.7
> .214
> .24.124.224
> .250.23.32
> .36.132.142
> .73
> 0.204.35.172
> 0.36.132.60
> 0.6.1.32
> 0.6.1.33
> 0.64
> 1.159.84
> 1.33
>
> Any ideas for a better regular expression to use?
>
> Thanks,
> Adrian
>
>
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