On 22.10.2010 06:05, Mathieu Bouchard wrote:
On Fri, 22 Oct 2010, Martin Schied wrote:
I wanted to use a fairly high a < 1 because then the phase for all
frequencies is approximately 90° off like for the ideal a=1. Using
slightly smaller factors and comparing input / output didn't satisfy
my expectations. maybe that would't matter at all - let's experiment...
How is the phase preservation an important thing for you ? I ask
because I didn't really think of it as important... (and I still
somewhat don't know when it's really important).
I think it's not important for a speaker simulation either, but my
assumption was that a correct behavior in phase would be a "sign" of a
working integrator.
that's indeed interesting. So the gain is defined for a constant
signal having the same input and output samples (or in other words DC
having no amplification) if I understood it correctly.
It's defined for any signal. There are different equivalent ways to
define the gain of a linear filter. In my head, I was thinking of an
input signal containing a single 1 in a sea of zeroes... but it might
be a bit easier to understand it using a constant input signal. Then
for [sig~ 1], [rpole~ 1] will diverge (as much as the float32 number
format can allow it to...) because 1/(1-1) is undefined (it's a
division by zéro). But for [sig~ 1] again, [rpole~ 0.999] will output
a constant 1000.
that's the way I understood it. fine!
Martin
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