If you normalize the output of the filter you describe to the same peak amplitude as the original, it's RMS value will certainly increase. Having the peaks at a common reference point is critical.
-Theron ^ On Tue, Jan 11, 2011 at 10:33 AM, Mathieu Bouchard <ma...@artengine.ca>wrote: > On Mon, 10 Jan 2011, Roman Haefeli wrote: > > Assuming that the more compression is applied, the more the RMS amplitude >> [1] approaches the Peak amplitude [2] of an audio signal, >> > > Why do you assume that ? Let's say I take a signal and divide it by its > recent peak volume. The output of [osc~] will stay unchanged. A signal made > of plenty of sharp spikes will have a much lower RMS/peak ratio and still be > unchanged. > > Are you confusing this with waveshaping such as [expr tanh($v1)] ? It may > be a special case of compression, but is not what is usually meant by that. > > http://en.wikipedia.org/wiki/Dynamic_range_compression > > > _______________________________________________________________________ > | Mathieu Bouchard ---- tél: +1.514.383.3801 ---- Villeray, Montréal, QC > > _______________________________________________ > Pd-list@iem.at mailing list > UNSUBSCRIBE and account-management -> > http://lists.puredata.info/listinfo/pd-list > >
_______________________________________________ Pd-list@iem.at mailing list UNSUBSCRIBE and account-management -> http://lists.puredata.info/listinfo/pd-list
