Le 2012-01-31 à 18:33:00, Lorenzo Sutton a écrit :
On 31/01/2012 16:07, Jonghyun Kim wrote:
expr $f1;
if ($f1 == 1, 1, 0);
if ($f1 == 5, 2, 0);
if ($f1 == 9, 3, 0);
if ($f1 == 13, 4, 0);
if ($f1 == 17, 5, 0);
if ($f1 == 21, 6, 0);
if ($f1 == 25, 7, 0);
if ($f1 == 29, 8, 0);
if ($f1 == 33, 9, 0);
if ($f1 == 37, 10, 0);
if ($f1 == 41, 11, 0);
if ($f1 == 45, 12, 0);
You could also use a [select] instead of [expr]. Something like
|
[sel 1 5 9 ... ]
| | | ... |
[1( [2( [3( ... [t b]
|
[0(
Now that I think of it, with GridFlow (any version), you have this :
[listfind 1 5 9 13 17 21 25 29 33 37 41 45]
|
[+ 1]
To get a single index from 1 to 12, or 0 if not found.
If you really need to send a zero for each time something is not found,
however, you can do this :
[#outer == (1 5 9 13 17 21 25 29 33 37 41 45)]
|
[# * (1 2 3 4 5 6 7 8 9 10 11 12)]
|
[#unpack 12]
||||||||||||
But because of the pattern of numbers involved (equally spaced), you could
use [mod 4] and [div 4] to separate $f1 into two parts, one part that
should be 1, and the other that should be between 1 and 12. That's quite a
shortcut.
______________________________________________________________________
| Mathieu BOUCHARD ----- téléphone : +1.514.383.3801 ----- Montréal, QC
_______________________________________________
Pd-list@iem.at mailing list
UNSUBSCRIBE and account-management ->
http://lists.puredata.info/listinfo/pd-list
