El 03/09/13 10:11, Lorenzo Sutton escribió:
On 03/09/2013 14:06, Mario Mey wrote:
IOhannes, you are right only in these cases:

0 127 0 500
0 300 0 1
...

But, if I need:

50 10 0 500|
(assuming you want to map have 50 mapped to the 'minimum'):
|
[- 10]
|
[t b f]
|   /
[-  ]
|
[* 12.5]
|

3000 -3000 0.5 0.6
[* -1]
|
[+ 3000]
|
[/ 60000]
|
[+ 0.5]

Yes, you can make this math every scale you need... or use an abstract that does the same automatically. In my patch, I use 284 lin-eq-conv objects. I didn't want to think how to make that math... and change everytime (normally, I create a lin-eq-conv and change its values a lot of times).

Best.



...

I will need a "linear equation conversion". As I wrote in last mail, I was needing something like this, first in ActionScript... then in Python... but I never could did it. Now, I needed again in Pd... so, I made lin-eq-conv.pd with extrapolation and lin-eq-conv-clip.pd for clipped values. I made it as neat as I could, to see how it works. Using x0-x1 and y0-y1, it uses expr to get "a" and "b" at load. Then, it only computes "aX + b = Y".

I attach the lin-eq-conv.pd, lin-eq-conv-clip.pd and lin-eq-conv-help.pd.

Also, I have some issues using [autoscale]. I start giving values and it outputs only 1. Then, I start to down the input and, then, it shows the real output. Maybe it's about this version (0.43.4 Pd-Extended 64bits).

PD: translated to Python:

|def lin_eq_conv(x, x0, x1, y0, y1):
   a = (y0 - y1) / (x0 - x1)
   b = (a * x0) + y0
   return a * x + b|




El 03/09/13 03:32, IOhannes zmölnig escribió:
On 09/02/2013 06:17 PM, hghoyer wrote:
Hi,

in Max/MSP there is an object for simple scaling.

If you create in MAX these object with this arguments:

[scale 0 127 0 500] incomming messages from 0 to 127 are automatically
scaled from 0 to 500...
honestly i'm of the firm conviction that you should learn how scaling
works: it really is only a matter of adding, multiplying, dividing,
subtracting - stuff you should heave learned in primary school.

as frank pointed out, this should do for you:

|
[/ 127]
|
[* 500]
|

if you find it too tedious to do the maths over and over again, you
might want to create an abstraction.


being able to solve trivial problems like this will surely empower you
to solve more complex problems :-)

gamsdr
IOhannes





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