Hey Matt, there's no need for the feedback path (and therefore no [block~ 1] ;-))
Just use the following formula: y[n] = (y[n-1] - x[n-k])/k where k is the number of samples to be averaged (must be at least 1). see the patch I sent to Alex in my last mail. it uses [rpole~ 1] for the y[n-1] part and [z~ k] for the x[n-k] part (you can replace the latter one with a [delwrite~] [delread~] pair to make it purely vanilla). The funny thing about linear moving average filters is, that although it can be implemented as a recursive filter (like in both our patches), it is still a FIR filter (and therefore it defeats the notion that recursive filters are always IIR filters). The impulse response is just a rectangular pulse and therefore finite. Gesendet: Dienstag, 08. Dezember 2015 um 07:13 Uhr Von: "Matt Barber" <brbrof...@gmail.com> An: "Alexandre Torres Porres" <por...@gmail.com> Cc: "pd-list@lists.iem.at" <pd-list@lists.iem.at> Betreff: Re: [PD] Moving Sum object? Something like this? Almost completely untestsed. :D On Tue, Dec 8, 2015 at 12:20 AM, Alexandre Torres Porres <por...@gmail.com> wrote: Talking about averages I wonder if we have an object that sums (in a moving average fashion) a series of samples cheers _______________________________________________ Pd-list@lists.iem.at[Pd-list@lists.iem.at] mailing list UNSUBSCRIBE and account-management -> http://lists.puredata.info/listinfo/pd-list[http://lists.puredata.info/listinfo/pd-list] _______________________________________________ Pd-list@lists.iem.at mailing list UNSUBSCRIBE and account-management -> http://lists.puredata.info/listinfo/pd-list[http://lists.puredata.info/listinfo/pd-list] _______________________________________________ Pd-list@lists.iem.at mailing list UNSUBSCRIBE and account-management -> http://lists.puredata.info/listinfo/pd-list
