A simple approach.
Am 29.09.24 um 21:08 schrieb Peter P.:
Hi list, I am having lists with a variable number of items and I want to break them up two lists dependent on the presence of a specific item. I can't seem to understand how to do it though. Here's a quick example of what I mean: 1 2 3 4 5 6 look for the number 4 and output two lists (at separate outlets) which are before and after that number 4, giving: 1 2 3 and 5 6 respectively I'd need the solution to work for lists of other lengths as well, i.e. 55 66 77 88 4 102 -33 should be broken up into 55 66 77 88 and 102 -33 alike. I tried [route] and [list] objects but can't get them to do what I want. thanks! P --- pd-list@lists.iem.at - the Pure Data mailinglist https://lists.iem.at/hyperkitty/list/pd-list@lists.iem.at/message/7EF2SASANM67WTX766GIKCN5OIR64PXN/ To unsubscribe send an email to pd-list-le...@lists.iem.at mailing list UNSUBSCRIBE and account-management -> https://lists.iem.at/
#N canvas 547 67 208 243 10; #N canvas 750 206 194 241 list-drip 0; #X obj 37 37 inlet; #X obj 37 152 list store; #X obj 37 83 until; #X obj 37 106 f; #X obj 67 106 + 1; #X msg 37 129 get \$1 1; #X obj 78 84 0; #X obj 37 175 outlet; #X obj 94 175 outlet; #X obj 37 60 t b b a; #X connect 0 0 9 0; #X connect 1 0 7 0; #X connect 1 1 8 0; #X connect 1 1 2 1; #X connect 2 0 3 0; #X connect 3 0 5 0; #X connect 3 0 4 0; #X connect 4 0 3 1; #X connect 5 0 1 0; #X connect 6 0 3 1; #X connect 9 0 2 0; #X connect 9 1 6 0; #X connect 9 2 1 1; #X restore 38 61 pd list-drip; #X obj 38 153 list store; #X msg 83 107 append \$1; #X obj 38 176 print; #X msg 136 38 4; #X obj 38 107 t b b; #X obj 107 84 t b b; #X msg 38 38 1 2 3 4 5 6; #X obj 38 84 sel; #X connect 0 0 8 0; #X connect 0 1 6 0; #X connect 1 0 3 0; #X connect 2 0 1 0; #X connect 4 0 8 1; #X connect 5 0 1 1; #X connect 5 1 1 0; #X connect 6 0 1 1; #X connect 6 1 1 0; #X connect 7 0 0 0; #X connect 8 0 5 0; #X connect 8 1 2 0;
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