If we create a few piddles of different types and cat them together, the output datatype is the same as the first piddle:
~~~perl $by=xvals(byte,5)+253; $so=xvals(short,5)+32766; $lo=xvals(long,5)+32766; $fl=float(xvals(5)+0.2); $c1 = cat($by,$so,$lo,$fl); $c2 = cat($lo,$so,$fl,$by); $c3 = cat($fl,$lo,$by,$so); print "\$c1: " . $c1->info . "$c1"; #is a byte print "\$c2: " . $c2->info . "$c2"; #is a long print "\$c3: " . $c3->info . "$c3"; #is a float ~~~ What I would expect is that the output has the same type as the piddle of the highest datatype. That way cat(@list_of_piddles)->dog would actually be a symmetric operation. Is that a reasonable expectation? 'glue' and 'append' both return a piddle of the highest input datatype. Is there a good reason to have the datatype be based on the first piddle for 'cat' only? It's not a hard change to make to 'cat', but I wanted to make sure I wasn't missing something. Derek ------------------------------------------------------------------------------ Check out the vibrant tech community on one of the world's most engaging tech sites, Slashdot.org! http://sdm.link/slashdot _______________________________________________ pdl-devel mailing list pdl-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/pdl-devel
