On 10 Feb 2005 at 11:14, Albano Garcia wrote: > > Ryan, > This is basic chinese for me :-) > All I need to know is if the claimed output gets > divided by the quantity of batteries being charged or > if not. > They sell it as a 2 and a half hour charger, (900 mnA > by 2,5 is 2250 mA, and my batts are 2300 mA), but I > don't know if it's true if 4 batts are being charged. > Thanks and regards
It's probably 2.5 hrs for 1600-1800mAh batteries but I'd assume 3 to 3.5hrs for a set of 2300mAh high capacity cells due to thermal losses dependant upon their initial state of discharge of course. If the charger is a good one they may take as little as 1.5hrs depending on how deep your equipment will let the batteries discharge before deeming them exhausted. Rob Studdert HURSTVILLE AUSTRALIA Tel +61-2-9554-4110 UTC(GMT) +10 Hours [EMAIL PROTECTED] http://members.ozemail.com.au/~distudio/publications/ Pentax user since 1986, PDMLer since 1998
