On Fri, Feb 15, 2002 at 03:08:22PM -0500, Peifer, William [OCDUS] wrote: > Nitin wrote, regarding the foot-pump dynamo to power your laptop computer: > > let see: a dell 4000 series laptop has a battery of 1800mAh at > > 14.8V.... [Snip] Thats ~22834.286 calories. > > > now acc. to > > http://diabeticgourmet.com/calculators/799run.shtml > > A perons weighing 150 pounds (kgs?) jogging 5 miles burns 489.75 > > calories. > > > To be able to foot-pump more energy than that in a few minutes seems > > totally impossible even with 100% efficiency. Either is a fiasco or the > > above conversions have a flaw :) > > Hi Nitin, > > The answer is that the thermodynamic calorie (with a lower-case "c") and the > metabolic or dietary Calorie (with an upper case "C") are not equal. The > metabolic Calorie is actually 1000 thermodynamic calories. A 150-pound > jogger actually burns about 490,000 thermodynamic calories (about two > million joules).
Ah yes, that explains it :). So the 22834.286 calorie is more like a 410 yards run at 100 efficiency of the gadget. Would that be too tiring to lazy folks ? :) - This message is from the Pentax-Discuss Mail List. To unsubscribe, go to http://www.pdml.net and follow the directions. Don't forget to visit the Pentax Users' Gallery at http://pug.komkon.org .