On 7/1/05, demerphq <[EMAIL PROTECTED]> wrote:
> The question you have to ask yourself is why should a reference be
> treated different from any other value? It is a VALUE.
> IE: why should
In the following part i meant to make it more clear:
by changing this line
>
> $x=1;$y=2;$z=3;
to
$x=1; $y=1;$z=2;
>
> $a1=[$x,$x];
> $a2=[$y,$z];
>
> $a1 and $a2 are different but
>
> $x={};$y={};$z={};
>
> $a3=[$x,$x];
> $a4=[$y,$z];
>
> $a3 and $a4 are not? Isn't the situation identical? Consider
>
> # add one to each of the arrays
> for my $ar ($a1,$a2,$a3,$a4) {
> $_=0+$_ @$ar;
> }
>
> so now the refs turn into their addresses and you will consider them
> different? This just doesnt make sense.
Sorry about that. Twitchy send finger. :-)
cheers,
--
perl -Mre=debug -e "/just|another|perl|hacker/"
