Should a non-breaking space character be treated as whitespace in perl source code? It doesn't appear to be:
$ xxd foo.pl 0000000: 2321 2f75 7372 2f62 696e 2f70 6572 6c0a #!/usr/bin/perl. 0000010: 7573 6520 7574 6638 3b0a 6d79 2024 6e6f use utf8;.my $no 0000020: 6272 6561 6b73 7061 6365 203d 2022 c2a0 breakspace = ".. 0000030: 223b 0a70 7269 6e74 2022 6d61 7463 6822 ";.print "match" 0000040: 2069 6620 246e 6f62 7265 616b 7370 6163 if $nobreakspac 0000050: 6520 3d7e 202f 5c73 2f3b 0a65 7869 743b e =~ /\s/;.exit; 0000060: 0ac2 a00a .... $ perl foo.pl Unrecognized character \xC2 at foo.pl line 6. Delete the last line and the program will work: $ perl foo.pl match Version of perl I'm using: $ perl -v This is perl, v5.8.7 built for cygwin-thread-multi-64int foo.pl should be attached. Cheers, Stephen PS. The reason I ask is that Ultra Edit inserts unicode code point FEFF (zero-width non-breaking space) at the beginning of UTF-8 encoded files *by default*. I happen to think that doing this by default is criminal, but it occurred to me that maybe perl shouldn't care.
foo.pl
Description: Perl program