Now I am meeting the problem: my codes is like:

**************************************************
$ldapsearch="/usr/bin/ldapsearch";
my $command = "$ldapsearch -x -LLL -h \"cds2.ford.com\" -b \"ou=People,
o=Ford,c=US\" \"uid=$login\" uid fordUNIXid";
print "print A ---------- $command";            
@verifyinfo = ldapsearch_result ($command);

sub ldapsearch_result
{
        my $command_line = $ARGV[0];    
        print "print B --------- $command_line\n";
        
}
************************************************

Print A I got:

/usr/bin/ldapsearch -x -LLL -h "cds2.ford.comi" -b "ou=People,
o=Ford,c=US" "uid=ldapdb3" uid fordUNIXid

Print B I got nothing

I do not understand that I have content in $command, why I get not get
it in the method? I am working on linux.\
Could anyone tell me why?

Thanks a lot in advance!!!!

Lixin

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