I didn't that part. oh well.
-----Original Message-----
From: Jing Wee [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 12, 2002 3:50 PM
To: Carlos Guillen
Cc: '[EMAIL PROTECTED]'; [EMAIL PROTECTED];
[EMAIL PROTECTED];
[EMAIL PROTECTED]
Subject: RE: A regular expression question
>while (<>) {
> if ( /^#/ ){
> print;
> }
>}
This will include the "#" which the original poster does not want.
>-----Original Message-----
>From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
>Sent: Thursday, September 12, 2002 3:12 PM
>To: [EMAIL PROTECTED];
>[EMAIL PROTECTED];
>[EMAIL PROTECTED]
>Subject: A regular expression question
>
>
>I have a cron file which the line looks like this:
>
>00 22 * * * perl -S queue_submit.pl esd-foundry "perl -S host-scrubber.pl"
>#build host scrubber
>30 22 * * * perl -S queue_submit.pl esd-foundry "perl -S group-scrubber.pl"
>#build group scrubber
>30 22 * * * perl -S queue_submit.pl esd-foundry "perl -S
object-scrubber.pl"
>#build object scrubber
>
>I want to get the comment after # of each line(not including "#"), how
could
>I do this?
>
>Thanks a lot in advance!
>
>Lixin
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