Hi Patrick, sorry I meant to say, if I try to make a path mkdir won't allow me to do that.
Like for example, $directory = "F:\this\is\a\test"; mkdir($directory,0777) won't work. Is there a make path function in PERL? I cannot seem to find one. thanks, John -----Original Message----- From: Patrick J. LoPresti [mailto:[EMAIL PROTECTED] Sent: Thursday, September 25, 2003 9:26 AM To: John Deretich Cc: 'SUMNER, Peter'; Perl-Win32-Admin-Request (E-mail) Subject: Re: s/ / / operator To get the file name, use the File::Spec or File::Basename module. They are more robust, portable, and readable than calling "split" by hand. Always invoke mkdir, or any similar Perl operator, like this: mkdir $directory, 0777 or die "Unable to mkdir $directory: $^E"; That will tell you exactly what it tried to do and why it failed. - Pat John Deretich <[EMAIL PROTECTED]> writes: > Thanks Peter, > > this works, but now PERL won't > allow me to make the directory > to copy the files in. > > I am using mkdir("$directory",0777). > > Any idea why? > > thanks, > > John _______________________________________________ Perl-Win32-Admin mailing list [EMAIL PROTECTED] To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
