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This works to a point...
Pattern = "~[^>]*/"
And then a /s on the remains, but I wish I could
get the ~ and / out so I don't have to do the /s.
Anybody?
----- Original Message -----
Sent: Tuesday, June 12, 2001 2:26
PM
Subject: RegEx stripping
I have a thousand rows of data that gets
displayed as such;
...
<li><a
href="http://www.comp.com/~len/">len</a> - Tennis Golf Health and
Computer Book Store<br>
<li><a
href="http://www.comp.com/~tmaki/">tmaki</a> - Toby
Maki/Intermedia<br>
...
I need to strip out the data between ~ and / and
then CSV the results, doing the CSV part is easy, it's the RegEx I'm stuck
with.
Something like this... ; SearchPattern =
"((\w+)\~([^\s]+\/\w))"
No I don't have the RegExp book, and yes I should
go buy it...
Thanks,
Mark
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