# I have a program that gets a hash from an API call.
# the format of the hash is that each key corresponds to an
# array. The following code snippet illustrates the data:
$href->{One} = [1,2,3,4];
print ref($href)."\n";
print ref($href->{One})."\n";
# I would like to simplify the syntax to use a simple array
# format by creating a new reference to the array to allow me
# to use the conventional syntax ie: $aref[0]
$aref = \@{$href->{One}};
print "$href->{One}=$aref\n";
# the output indicates that it did this...
# but this next line does not give the expected results
print "$href->{One}[0]=$aref[0]\n";
print "$href->{One}[0]=$aref->[0]\n";
#1. can I create a reference to this array that will allow me to
# access it without the -> operator?
#2. is there a simple explanation why I still need the -> operator?
#Howard Jares
#University of Houston
#Due to the current budget constraints, the light at the end of the tunnel
will be turned off until further notice.
_______________________________________________
Perl-Win32-Users mailing list
[EMAIL PROTECTED]
To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
