Chris Wagner wrote, on Thu 6/30/2005 08:48
Joseph P. Discenza, Sr. Programmer/Analyst
mailto:[EMAIL PROTECTED]
Carleton Inc. http://www.carletoninc.com
574.243.6040 ext. 300 fax: 574.243.6060
Providing Financial Solutions and Compliance for over 30 Years
: Wow there's been a lot of heavy duty code proposed to do
something so
: simple. The answer is in how Perl converts between the
two.
:
: print "is a number" if $var eq $var + 0;
: print "not a
number" if $var ne $var + 0;
Except if $var is, say, '0.00'. Then $var + 0 is '0', and
won't eq $var.
Joe
==============================================================Joseph P. Discenza, Sr. Programmer/Analyst
mailto:[EMAIL PROTECTED]
Carleton Inc. http://www.carletoninc.com
574.243.6040 ext. 300 fax: 574.243.6060
Providing Financial Solutions and Compliance for over 30 Years
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