On Wed, Feb 02, 2005 at 07:04:51AM -0500, Erick Bourgeois wrote:
> The documentation for strtod states the following:
>
> if (($str eq '') || ($n_unparsed != 0) || !$!)
>
> However, if you negate $!, I believe this has the opposite effect of
> what you *really* want to test. If $! remains 0, this means strtod was
> successful. Should it not be?:
>
> if (($str eq '') || ($n_unparsed != 0) || $!)
Well-spotted. Fixed by the change below. The next line was wrong too!
--
Fire extinguisher (n) a device for holding open fire doors.
Change 23921 by [EMAIL PROTECTED] on 2005/02/02 18:25:00
fix POSIX::strtod error handling documentation
Affected files ...
... //depot/perl/ext/POSIX/POSIX.pod#42 edit
Differences ...
==== //depot/perl/ext/POSIX/POSIX.pod#42 (text) ====
@@ -1342,8 +1342,8 @@
The second returned item and $! can be used to check for valid input:
- if (($str eq '') || ($n_unparsed != 0) || !$!) {
- die "Non-numeric input $str" . $! ? ": $!\n" : "\n";
+ if (($str eq '') || ($n_unparsed != 0) || $!) {
+ die "Non-numeric input $str" . ($! ? ": $!\n" : "\n");
}
When called in a scalar context strtod returns the parsed number.
