# New Ticket Created by "brian d foy" # Please include the string: [perl #130184] # in the subject line of all future correspondence about this issue. # <URL: https://rt.perl.org/Ticket/Display.html?id=130184 >
Adapted from the Stackoverflow answer at: http://stackoverflow.com/a/40824226/2766176 I'm using moar (2016.10) on macosx (10.10.5) darwin (14.5.0) (These variables are quite nice!) This came out of a problem I had with set membership. It turns out that the way you make the set matters, and the way you make the candidate member matters. In my case, there's a bug with angle-bracket word quoting. I used the [angle-brackets form of the quote words](https://docs.perl6.org/language/quoting#Word_quoting:_qw). The quote words form is supposed to be equivalent to the quoting version (that is, True under `eqv`). Here's the doc example: <a b c> eqv ('a', 'b', 'c') But, when I try this with a word that is all digits, this is not equivalent: $ perl6 > < a b 137 > eqv ( 'a', 'b', '137' ) False But, the other forms of word quoting are! > qw/ a b 137 / eqv ( 'a', 'b', '137' ) True > Q:w/ a b 137 / eqv ( 'a', 'b', '137' ) True The angle-bracket word quoting uses [IntStr](https://docs.perl6.org/type/IntStr): > my @n = < a b 137 > [a b 137] > @n.perl ["a", "b", IntStr.new(137, "137")] Without the word quoting, the digits word comes out as [Str]: > ( 'a', 'b', '137' ).perl ("a", "b", "137") > ( 'a', 'b', '137' )[*-1].perl "137" > ( 'a', 'b', '137' )[*-1].WHAT (Str) > my @n = ( 'a', 'b', '137' ); [a b 137] > @n[*-1].WHAT (Str)
