On Tue, 04 Apr 2017 02:52:53 -0700, comdog wrote: > I originally asked about this on Stackoverflow > (http://stackoverflow.com/q/43199427/2766176) > > This `try` catches the exception: > > try die X::AdHoc; > say "Got to the end"; > > The output shows that the program continues: > > Got to the end > > If I attempt it with `shell` and a command that doesn't exit with 0, > the `try` doesn't catch it: > > try shell('/usr/bin/false'); > say "Got to the end"; > > The output doesn't look like an exception: > > The spawned command '/usr/bin/false' exited unsuccessfully (exit code: > 1) > in block <unit> at ... line ... > > What's going on that this makes it through the `try`? > > --- Perl variables --- > Perl: Perl 6 > Executable: perl6 > Flavor: Rakudo 2017.01 > VM: MoarVM 2017.01 > Distro: macosx > Kernel: darwin > PERL6LIB: > > --- Other Environment --- > LANG: en_US.UTF-8 > LANGUAGE: en_US.UTF-8 > LC_ALL: en_US.UTF-8 > LESSCHARSET: utf-8 > LOCALE_I_WANT: en_US.UTF-8 > LOCAL_PATH: /usr/local/bin > SHELL: /bin/bash > SHLVL: 1 > TERM: vt100
Thank you for the report. However, there's no bug here. try catches exceptions. shell() doesn't throw, but returns a Proc object. Proc objects with non-zero exist status throw when sunk. So in your code, the try gives a Proc object a pass, it immediately gets sunk, and explodes (outside of try). You can use `try sink shell '/usr/bin/false'` to get it to explode inside of try. We also have a support channel where you can ask questions like this one: https://webchat.freenode.net/?channels=#perl6
