On Mon, Aug 6, 2018 at 4:59 PM ToddAndMargo <toddandma...@zoho.com
<mailto:toddandma...@zoho.com>> wrote:
Hi All,
How do I assign a string that looks like an integer
into an interger?
$str = "601" -- > $int = 601
Many thanks,
-T
On 08/06/2018 02:01 PM, Brandon Allbery wrote:
Prefix + numifies, prefix ~ stringifies.
pyanfar Z$ 6 'my Str $a = "5"; dd +$a'
5
pyanfar Z$ 6 'my Int $a = 5; dd ~$a'
"5"
What is this all about?
$ p6 'my Int $y = 7; my Str $x = dd ~$y; say $x'
"7"
(Str)
Why does it say "(Str)"? The confirmation is nice, but
why is it printing out?
And why does this error out?
$ p6 'my Int $y = 7; my Str $x = dd ~$y; say "$x"'
"7"
Use of uninitialized value $x of type Str in string context.
Methods .^name, .perl, .gist, or .say can be used to stringify it to
something meaningful.
in block <unit> at -e line 1
