Yes, [] acts on the result (a positional, e.g. a list) returned by function or method, it does not act on the function or method itself.
You have more or less the same in Perl 5, for example: my $first_item = (split /;/, $string)[0]; Here, the [0] acts on the list returned by split. Le mar. 2 oct. 2018 à 08:05, ToddAndMargo <toddandma...@zoho.com> a écrit : > On 10/1/18 3:37 PM, Donald Hunter wrote: > > toddandma...@zoho.com (ToddAndMargo) writes: > >> > >> Hi Curt, > >> > >> Perfect! Thank you! > >> > >> So all methods that respond with --> Positional will accept [] > >> > >> Awesome! > >> > >> -T > > > > Not quite. > > > > All methods that respond with --> Positional, provide a Positional that > > will accept [] > > > > Methods don't accept [], values that are positional do that. > > > > Cheers, > > Donald. > > > > Hi Donald, > > I am confused. I though we both said the same thing? > Is your distinction that [] is actually a routine in itself > and not part of the method? And I am lumping them together? > > -T >
