On Tue, Oct 9, 2018 at 9:27 AM Laurent Rosenfeld via perl6-users < perl6-us...@perl.org> wrote:
> This: > my $f = $fh.lines; > will slurp all the lines into $f (but you can still access the individual > items with something like $f[4]). > Is that true? I supposed that it would hold the Seq as a scalar (un-iterated) Seq. I know that my @f = $fh.lines will slurp it all, but I thought you could avoid that by assigning it to a scalar. Curt
