OK .. I mistakenly assumed that it should not compile from the doc
'(This does not work with the &zape variable)'.
my $tmp = Foo::Bar::<&zape>;
say $tmp(); # zipi - works
if ';; $_? is raw' is the signature, what does the ';;' mean and what
does '#`(Block|62717656) ...' mean?
On 10/11/18 9:45 AM, Siavash wrote:
It means it's returning a Block.
dd Foo::Bar::<&zape> # Block &zape = -> ;; $_? is raw {
#`(Block|94777643161752) ... }
say Foo::Bar::<&zape>() # zipi
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