On 1/11/19 11:16 AM, Bruce Gray wrote:
On Jan 11, 2019, at 12:41 PM, ToddAndMargo via perl6-users
<perl6-us...@perl.org> wrote:
Hi All,
How do I do a hash inside a hash?
So far I have:
$ p6 'my %Vendors=("acme" => ( "ContactName" => "Larry, "AccountNo" => 1234 )
); say %Vendors;'
===SORRY!=== Error while compiling -e
I want to be able to have both a Contact Name and and AccountNo
associated with each key in %Vendors.
Many thanks,
-T
First, you need a double-quote after `Larry` (before the comma) to fix the
syntax error:
perl6 -e 'my %Vendors=("acme" => ( "ContactName" => "Larry", "AccountNo"
=> 1234 ) ); say %Vendors;'
At this point, you have a Hash of List of Pairs. To change it into a Hash of
Hashes, change the inner parens to curly braces:
perl6 -e 'my %Vendors=("acme" => { "ContactName" => "Larry", "AccountNo" => 1234 }
); say %Vendors; say %Vendors<acme><AccountNo>;'
Those inner parens were acting as an anonymous list constructor, but you needed
an anonymous *hash* constructor, which is what the curly braces do (when they
are not doing their code-block-ish job).
You could have also used `Hash(…)` or `%(…)` instead of `{…}`, but `{…} is
shortest, and most traditional from Perl 5.
—
Hope this helps,
Bruce Gray (Util of PerlMonks)
Hi Bruce,
Thank you!
This works,
$ p6 'my $x="Ace"; my %Vendors=("acme" => { "ContactName" => "Larry",
"AccountNo" => 1234 }, "Ace" => { "ContactName" => "Mo", "AccountNo" =>
"A102" } ); say "%Vendors<Ace><ContactName>" ~ "\t" ~
"%Vendors<Ace><AccountNo>";'
Mo A102
but I have to access it by a variable. "Now" what am I doing wrong?
$ p6 'my $x="Ace"; my %Vendors=("acme" => { "ContactName" => "Larry",
"AccountNo" => 1234 }, "Ace" => { "ContactName" => "Mo", "AccountNo" =>
"A102" } ); say "%Vendors<$Ace><ContactName>" ~ "\t" ~
"%Vendors<$Ace><AccountNo>";'
Use of uninitialized value of type Any in string context.
Many thanks,
-T
