Mea culpa. Super embarrassing.
Comes from having to do something else for a year.
Thanks Brad
On 03/01/2021 18:59, Brad Gilbert wrote:
You've already asked a similar question.
https://stackoverflow.com/questions/54033524/perl6-correctly-passing-a-routine-into-an-object-variable
<https://stackoverflow.com/questions/54033524/perl6-correctly-passing-a-routine-into-an-object-variable>
When you call $a.f() you are getting the value in &!f which is a function.
When you call $a.f().() you are getting the value in &!f, and then
also calling that function.
You don't need the parens on a method call if they are empty.
So $a.f() is the same as $a.f
and $a.f().() is the same as $a.f.()
On Sun, Jan 3, 2021 at 12:30 PM Richard Hainsworth
<rnhainswo...@gmail.com <mailto:rnhainswo...@gmail.com>> wrote:
I was playing with classes and adding a closure to an attribute.
I discovered that to call a closure on object I need `.()` rather
than just `()`. See REPL below.
raku
Welcome to 𝐑𝐚𝐤𝐮𝐝𝐨™ v2020.12.
Implementing the 𝐑𝐚𝐤𝐮™ programming language v6.d.
Built on MoarVM version 2020.12.
To exit type 'exit' or '^D'
> class A { has &.f = -> { 'xyz' }}
(A)
> my A $a .=new
A.new(f => -> { #`(Block|94272504746848) ... })
> say $a.f()
-> { #`(Block|94272504749656) ... }
> say $a.f.()
xyz
>
I was wondering whether it was intended for `()` to return
something other than `.()`?
My first thought would be that `.()` would have the same syntactic
sugar as `.[]` on an Array object.
I looked in the Documentation and in Classes found
&!callback();
inside class Task.
So I think there may be something a bit wrong. Or is this an
artifact of REPL?
