Assuming that all you are trying to do is to delete everything at the start
of a line up to and including that string, the first thing I would do is
get rid of all the superfluous parts of the regex.
Does
$NewRev ~~ s/ .* 'Release Notes <strong>V' //
have the problem?
".*" means any number of characters, including zero; thus the "?" is
superfluous.
The parentheses simply capture the data that is matched, Since the string
is constant, there is not much use capturing it, and I doubt you are using
the captured value (available as $0).
Kevin.
On Sun, 24 Oct 2021 at 10:44, ToddAndMargo via perl6-users <
perl6-us...@perl.org> wrote:
> Hi All,
>
> Wish I had a Q[;;;] expression inside a regex, but I don't
>
> This is my notes on how to do a regex with a special
> characters in it:
>
> Regex with literals in it:
> $JsonAddr ~~ s| (';') .* ||;
>
> It "usually" works.
>
>
> Unfortunately this one hangs my program (I am slicing
> up a web page):
>
> $NewRev ~~ s/ .*? ('Release Notes <strong>V') //;
>
> I need a better way of doing the above.
>
> Many thanks,
> -T
>
>
>
