On 6/18/22 21:13, ToddAndMargo via perl6-users wrote:
Hi All,
What am I doing wrong here:
> my Buf $y = Buf.new( 0xFA xx 10);
Buf:0x<FA FA FA FA FA FA FA FA FA FA>
> $y ~= 0xBB.encode.Buf;
Buf:0x<FA FA FA FA FA FA FA FA FA FA 31 38 37>
I got three entries (31 38 37) instead of one (0xBB)
Some more goofing around:
> $y ~= 0xBB;
Stringification of a Buf is not done with 'Str'. The 'decode' method
should be used to convert a Buf to a Str.
in block <unit> at <unknown file> line 1
[10] > $y += 0xBB;
Type check failed in assignment to $y; expected Buf but got Int (201)
in block <unit> at <unknown file> line 1
Many thanks,
-T
Figured it out. Use `append`:
> $x
Buf:0x<41 42 43 44>
> $x.append( 0xDD );
Buf:0x<41 42 43 44 DD>
> $x.append( 0xEE..0xF1 );
Buf:0x<41 42 43 44 DD EE EF F0 F1>
> $x.append( 0xA1, 0xA3, 0xA5 );
Buf:0x<41 42 43 44 DD EE EF F0 F1 A1 A3 A5>
