Perhaps not really what you're intending, but here's how I'd start:
$ raku -e 'my $x="1.2.3.4"; $x ~~ s!\d+$!0/24!; say $x;'
1.2.3.0/24
The pattern part of the substitution matches all of the digits at the end of
the string (\d+$), then replaces them with the string "0/24". Everything prior
to those digits is left alone.
On Mon, Apr 29, 2024 at 05:45:49PM -0700, ToddAndMargo via perl6-users wrote:
> On 4/29/24 17:42, ToddAndMargo via perl6-users wrote:
> > Hi All,
> >
> > I thought I understood ^ and ? used in a regex'es,
> > but I don't.
> >
> > ^ means from the beginning and ? from the end.
I think you mean "$" here instead of "?".
Pm
