krish:
# I am a beginner in Perl and have a very trivial query. I have
# some .expect
# files in my directory structure which are spread all
# throughout. I want to
# convert these files (only expect files) to .expect.bak.
# Please let me know
# as to how this can be done using Perl script. Even pointers to shell
# scripting will help.
This is the wrong group for this sort of question. perl6-internals is
for the development of the upcoming release 6.0 of Perl; see
www.parrotcode.org for more information. Some more appropriate forums
for this sort of question:
-E-mail lists:
[EMAIL PROTECTED]
-Newsgroups:
comp.lang.perl.misc
-IRC:
DALnet #perl
-Web:
www.perlmonks.org
www.perlguru.org
(Note to p6i subscribers: send any suggested additions to this list to
me privately--I'm looking to create a template for these sorts of
messages.)
As far as your query, I suggest you look at the following features in
the Perl documentation (man pages, the 'perldoc' program, or at
www.perldoc.org):
-The 'eq' (string equality) and '.' (concatenation) operators (in
perlop).
-The opendir(), readdir(), closedir(), and rename() built-in functions
(in perlfunc).
HTH.
--Brent Dax
[EMAIL PROTECTED]
Configure pumpking for Perl 6
"Nothing important happened today."
--George III of England's diary entry for 4-Jul-1776
